bearings

[rugged zealot]

I don’t get this

[upbeat kelp]

The angle of depression is labelled incorrectly

It means 23 degrees from the horizontal

Also the triangle you form should have 500m as hypotenuse

[rugged zealot]

I probs sound stupid but what’s that

[upbeat kelp]

Not a stupid question at all. Essentially draw a dashed-line from A that is horizontal. The angle of depression is 23 degrees below that line

So the angle between the horizontal and the 500m line

[rugged zealot]

ohhh alr

So

what would my triangle look like

[upbeat kelp]

Your triangle would have hypotenuse that is the 500m line

And you want to calculate the vertical height so the side on the left

[rugged zealot]

I still have no idea sorry

[upbeat kelp]

That's okay. So do you understand where the 23 degrees is from the image I sent

[rugged zealot]

Yes

[upbeat kelp]

And the question asks for the vertical height. That is referring to the vertical line on the left in our triangle

[rugged zealot]

okay

[upbeat kelp]

So we can use the sine rule here

[rugged zealot]

idk that but we get given that in the exam now

I think

[upbeat kelp]

Okay I see. Well essentially it states that (sinA)/a = (sinB)/b

In this case let's say sinA is sin90 and side a is 500m

So 500/sin(90) = x/sin(23).
We can flip the sine rule too

[rugged zealot]

oh okay so 500/sin(90) is= sinb?

[upbeat kelp]

=x/sinB where x is the missing side and B is 23 degrees

[rugged zealot]

Ohhhh alr

so

is the 23 in the triangle?

the right angled one