#Trig
66 messages · Page 1 of 1 (latest)
It’s in a factorised form so you can equate each bracket to 0
the solutions i believe were something like x = 180, 270 and one more, how would i end up with that if i equated them to 0?
When is cosx 0
ik but like how would u evaluate it out?
cosx=0
x=cos^-1(0)
then use facts about cos to work out subsequent solutions in the given range
yeah i looked a little online and found out, but im still not sure how 270 is a solution, unless the answer book thing is wrong
but ty
360-90
=270
or just look at cos
and when your y=0
it crosses twice
oh right, wait, would 0 be considered a positive then when looking at the cast diagram?
x = 90, 270, 360?
positive tho
how come, its decently fast no?
at least the way my teacher taught it
ahh ok ty
just try using a graph
it ends up being easier
and there's just rules you can learn
ehh, cast isnt too hard for me ig
to skip using cast entirely
like I know tan will always repeat 180
sin is 180-theta
Cos is 360-theta
I can do it
u think u could help me with one, its a proof but with a triangle that isnt 90 degrees
I can try lmao
alr, one sec lemme get it
whether I can do it tho different story
its not the best pic cus its on a textbook but its 3(b)
unless im stupid, no clue how to do it
oh wait, this is double angles not compound, my bad
Whats β in terms of α
i can say i have absolutely no clue
yoo i got close kinda, cos2alpha = 7/25
@thick skiff
3a?
no, 3b
cant you work out a from part a
??
Well cos(90-a) is 6/10
dont think so but i have really no clue
So square it double it minus 1
aint that for 2x? or 2a
Cos(2A)=2cos(A)^2 - 1 where A = 90-A
cos(180-2α) = -cos(2α)
sin(2α) = 24/25 so cos(2α) = 7/25
So cos(β) = -7/25
am i dmb or something, did not know that cos(180-2a) = -cos2a
You can look at the unit circle