#trig identities
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do something like this: replace 2x with A, use trig identities to get a hidden quadratic, solve for A
ezpz 😎
$2\cos^2a - \cos{a} - 1 = \sin^2a$
i love skips!!!! :3
you get this beautiful equation
and then you can use good old $\sin^2a + \cos^2a = 1$
i love skips!!!! :3
rearrange to get a quadratic in terms of cos(a), solve for cos(a), find 2x
,w 2(cos(2x))^2 - cos(2x) - 1 = sin(2x)^2