#Vectors
18 messages · Page 1 of 1 (latest)
what is the normal vector of the plane x - 2y = 0?
bc if u work that out, yk that v will be perpendicular to that normal vector, and u can use the definition of the dot product to find information about a, b and c
isnt it just (1,-2,0)
so i know that the +ve z axis is (0,0,1) and cos60=1/2 and also dot producting abc with (1,-2,0) =0. But i got a pile of info that idk how to link.
yeah
im not sure what to dot product tho
use the fact that a . b = |a||b|cosθ
are we leaving v as (a,b,c)?
yeah
so v . (unit vector in z direction) = cos(60)
from there u should be able to solve for a, b and c hopefully
may have to use the fact that the magnitude is 1
i got 3c^2=a^2+b^2
what does size 1 even mean in this context
it means a^2 + b^2 + c^2 = 1