n2L on an inclined plane | Revision Server | Page 1

copper pivot Jan 27, 2024, 1:01 PM

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How do I calculate or find the force driving the particle upwards, they only give the acceleration

hardy pewter Jan 27, 2024, 4:02 PM

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Use F=ma

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And did you do 0.4*3gcos30

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To get the frictional force

copper pivot Jan 27, 2024, 9:35 PM

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Yeh

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But hi ow do I get the force going opposing to the friction

hardy pewter Jan 27, 2024, 9:37 PM

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Do you mean up the slope

copper pivot Jan 27, 2024, 9:57 PM

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Nah I got it

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I didn't realise there was no force pushing it upwards

#n2L on an inclined plane