#Complex numbers
16 messages · Page 1 of 1 (latest)
My initial idea was to turn that complex number into Euler form: √6 ⋅ e^(-πi/4)
Then since it's a triangle, it must have 3 vertices so multiply by w and w^2 where w = e^(2πi/3) to find the two other vertices.
However, I am wrong and I think it has something to do with the equilateral including O in the triangle, can someone help
I'd draw an argand diagram first to visualise it
So to get b you need its r and its argument
And you know that the triangle is equilateral so all sides are equal and you have A given
So the r of B must be equal to the r of A
use pythagoras to get that
Now to get the argument you know that all angles in an equilateral are 60
You'll need to get the argument of A first which is –45 degrees
So on your diagram you'll see that for the angle AOB to be 60 you must go above the real axis 15 degrees or move from the negative Imaginary axis 45 degrees ACW or to the left
You can now easily get the argument of B
And you have its r
@tame epoch
Obvi you should work in radians not degrees
Thanks, it makes sense