Logs, pls help | Revision Server | Page 1

red dragon Sep 23, 2023, 2:42 PM

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wait

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nvm

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i think i just set y = 0 then i have it

gloomy fog Sep 23, 2023, 2:42 PM

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$$\text{We want the x axis so when y = 0 }$$ \ \ $$log_3(x - 4) + 2 = 0 \implies log_3(x - 4) = - 2 \implies (x - 4) = 3^{-2}$$ \ $$\therefore x = 4 + \frac{1}{9}$$

drifting hollyBOT Sep 23, 2023, 2:43 PM

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AmbivalentChamp

red dragon Sep 23, 2023, 2:43 PM

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thanks lol

gloomy fog Sep 23, 2023, 2:43 PM

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I didn't see ur msg lool

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my b

#Logs, pls help