#please help
14 messages · Page 1 of 1 (latest)
i got that far but the other side i couldnt do
angle at circumference 1/2 angle at centre so JOM becomes 160
so 160 = x + 52
so x = 108
14 messages · Page 1 of 1 (latest)
opposite angles in cyclic quadrilateral sum to 180 therefore JOL = 52
i got that far but the other side i couldnt do
angle at circumference 1/2 angle at centre so JOM becomes 160
so 160 = x + 52
so x = 108