can someone please explain how to do part b and c
#differentiation
wise pewter
can someone please explain how to do part b and c
- For b) the coordinate for P is (2,10). For Q you have to put x = 2+h into y = 3x^2 - 2. You'll get the coordinate of Q to be (2+h,y), with y being that whole thing. You can then do m = (y - y1) / (x - x1) to find the gradient in terms of h
- If you're aware of differentiation by first principles, c) is pretty simple. When h in answer b) is minimised to 0 and you input x = 2, it becomes the answer in a)
near flower
- For b) the coordinate for P is (2,10). For Q you have to put x = 2+h into y = ...
thank you