#maths question
55 messages · Page 1 of 1 (latest)
ok
Do red and blue but don't put the probability
So all we know is that the combined probability of a blue being taken and another blue being taken is 1/20
ye
That means 1/4 × some probability = 1/20
Yes
So that's the probability that a blue counter is taken given that a blue counter has already been taken
ye
Can you send the probability tree you have so far?
Alr
Sorry I'm trying to think give me a minute
nw
Alright, so that means that because 1/5 is the probability of getting a second blue, the second red one would be 4/5 (because it's 1 - 1/5)
ok
Why can't I do this 😭 give me a minute again
ye no worries
it has this on the website
but i dont know what half of it is
i mean i guess
but i wouldnt be able to replicate it
Yeah that's 16 just did it
That's an interesting way though I didn't think of that
where is the 16 from
Well when it has these kind of questions I like to start by putting everything in the same variable, it becomes very easy from then on. If you use two, it still works but I don't like it personally
so ther is an easier way?
No
It's using x as the amount of blue counters at the start and 3x as the red counters at the start, then equating all of them to get x=4
ah
The model answer is very well done
Yes