Keep getting 2root 3 cos t

[glossy oak]

and can someone help with part b

[marble dagger]

i think you can square the x equation and the y equation

maybe not acc the argument isn't the same

Yeah i got it

basically

@glossy oak

find cos(t)

find sin (t)

use sin^2 + cos^2 = 1

and sub in

[glossy oak]

alr ill try 1 sec

wait cost t is qyite hard to find

[marble dagger]

nah

[glossy oak]

itll be quite long

[marble dagger]

you have x+y = root 3 cost

its only 1 step

[glossy oak]

ohhhh i see what you mean now

[marble dagger]

nice

[glossy oak]

ty

[marble dagger]

np

[glossy oak]

also could u have a look at question 1

and see if u get 2root 3

cause thats what im getting as x+y

[marble dagger]

that's what ur meant to get i swear

2root 3 cos 3

cost

[glossy oak]

so just a single root is the same as 2 root

[marble dagger]

there's a mistake in the question brother

100%

i don't see how you can get root 3 cos(t)

its definitely 2root 3 (cos(t))

[glossy oak]

yh i was gonna say