#Help
17 messages · Page 1 of 1 (latest)
set them equal to each other and solve
no
you need to show that until the first sequence hits 40 or more and the 2nd sequence hits below 1, they share only one term
it would be 31, which is n=4 in the first sequence and n = 3 in the 2nd
easiest way would just be to list all the terms
the question is worded very badly
as 40-n^2 is a decreasing sequence it won’t go above 40. as 2n^2 -1 will always be positive, they will share a term between 0-40. so show that value
What?
Why wouldn't you just set them equal to each other, find the 2 solutions of the quadratic and state that one of the solutions of the quadratic is ≤0 but in nth terms n>0
Or you might get a fraction as a solution for n
n is an integer in a sequence
so you cannot do that
you cant do this
since the sequences can share terms that are not in the same position
hence you’d need to list the terms
Wait ye i probably shouldn't be trying to correct anybody at 1am...