#quadratic graphs

7 messages · Page 1 of 1 (latest)

simple hollow
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how do i do part B

radiant grail
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For part b if you subtract x^2 from both sides, you get 0 = 2x + 6 - x^2
which is equal to the graph y = 2x + 6 - x^2 when y = 0
So you essentially just need to find the points where the graph crosses the x-axis, those are the roots

simple hollow
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okay thank you

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would it be 1.8 and 3.8?

winged dune
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there wont be a range as a the graph is drawn for u

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acc idk

simple hollow
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thank you both