How u do 9) ii)
#root
hybrid cove
terse nimbus
You replace in the original function wherever you see x with (x -2) or in other words give x - 2 as input instead of x
Then put that into the form f(x-2)=(x-a)(x-b)(x-c)
a b c are the roots as regular
nova oriole
Can't u just work out the roots from original equation
Like let's say original root of f(x)=3, new root will be 1?
hollow apex
Like let's say original root of f(x)=3, new root will be 1?
the new root would be 5
cause it's a transformation of the entire graph 2 to the right
hollow apex
Can't u just work out the roots from original equation
that is basically what nazli has done
but just a bit more formally, without the use of graph transformations
nova oriole
I see