#trig
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Area of a triangle = (b x c x sinA)/2
Angle A is found by rearranging the cosine rule (a^2 = b^2 + c^2 - 2bccosA) to cosA = (b^2 + c^2 - a^2)/2bc
A = arccos(cosA)
Substitute a, b, and A into the area formula
@severe compass