help

[languid marten]

S = 9,500
U = 0
V=
A=9.8
T =
U is 0 as the object is vertically falling
Use an equation with those 3 values and t to find time

these are the equations ur given in the exam (i assume)
s = 1/2(u+v)t
v^2 = u^2 + 2as
s = vt - 1/2at^2
a = (v-u)/t
s = ut + 1/2at^2
choose one that has ur 3 values and t

look for one that has S, U, A, T

s = ut + 1/2at^2 has these values
so input the values u got and then make t the subject

[languid marten]

well you need to substitute the values you have, and move them to a side so that t is by itself

so if you substitute, it would be
9,500 = 0 + 4.9t^2
now you can rearrange and make t the subject

[languid marten]

Do you know how to rearrange this equation?

[graceful citrus]

bloody hell

[languid marten]

Ok so divide both sides by 4.9 so get t^2 = 9500/4.9

then square roots both sides so t = sqrt(9500/4.9)