modelling.. | Revision Server | Page 1

tight umbra Dec 13, 2022, 9:11 PM

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Does anyone know how to do part b?

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I formed an equation 80,000=100-6.25(x-9)^2
Then tried solving for x but Im getting nowhere near the answer in the markscheme

quick trout Dec 13, 2022, 9:12 PM

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so they made more the 80,000 which means P>80

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remember it says P is measured in thousands of pounds

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so its 80 not 80000

tight umbra Dec 13, 2022, 9:12 PM

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Ohhh

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I done it using 80,000 thats why it probably didn’t work

quick trout Dec 13, 2022, 9:15 PM

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shouldnt the sign be the other way around too

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and just use a calc for this icl

#modelling..