is dis right

[dull grove]

.

||OA = a
OB = b
OC = c
OD = d
PS = PA + AS = (c-b)/2
QR = QD + DR = (c-b)/2
PQ = PB + BQ = (d-a)/2
SR = SC + CR = (d-a)/2
Two pairs of parallel sides thus a parallelogram||

[mystic kernel]

no

answer i s 7

[dull grove]

<@&791435371564892232> daddies

fuck you liam

[elder prawn]

sorry where have you gotten O from?😭

[dull grove]

O like origin

theyre position vectors

[elder prawn]

yeah but where is O on the diagram

[dull grove]

its not

theyre position vectors

O can be anywhere

[elder prawn]

im a tad confused i thought the point of position vectors were that they were measured in i and j?

like your reasoning to find two pairs of parallel sides makes complete sense otherwise

[dull grove]

doesnt have to be i and j

[elder prawn]

idk maybe that’s just the way i’ve been taught haha

but in that case idk how to help, apologies

[lofty island]

best approach is to take ln of the apex, then cube root the particle B as it accelerates towards the epicentre of the base and finishing off by integrating any right angles

[dull grove]

Yeah I thought about that and I knew once I found the circumcentre of the triangle formed from particle B as it flies through the fourth dimension the rest is trivial however it may be hard to prove the trajectory of the particle assuming it is a bose-Einstein condensate

[lofty island]

i mean

it's a lot easier to prove using Big-O notation

[dull grove]

That’s true if I just use l’hospitals then the Cauchy-Schwarz inequality I can prove it easily