lunar fog
#Logarithm
gentle echo
logxa-logxb=logx(a/b)
so first one is the same as loga(36)-loga(3) so loga(36/3)=loga(12)
gentle echo
sorry i went for food
second one is loga(a^3) which is 3, + loga(a^-1) which is -1, so 3-1=2
the next bit is just common log laws, so b=a^c
last one you should make it 1 log, so 2log(x+7)= log(x+7)^2 and youre subtracting log(x+5) so you divide by that, so you get log(((x+7)^2)/(x+5))=3
as the log is base 2 u can do 2 to the power of both sides
so (x+7)(x+7)/(x+5)=8
multiply both sides by x+5 so (x+7)^2=8x+40
then expand left side so x^2+14x+49=8x+40 and just subtract 8x+40 to get normal quadratic, x^2+6x+9=0