probability 3 | Revision Server | Page 1

minor summit Nov 8, 2022, 8:32 PM

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Can someone help this too

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🙏🙏

shell pelican Nov 8, 2022, 9:55 PM

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Hi, I think I know how to help.

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You are on the right track

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However there is one more step you need to do

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I am guessing you got 0.46 by (0.3x0.6) + (0.7x0.4)

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Which would be partially correct

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However

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I’m the question it does say at least one.

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So you need to take into consideration at waiting at both sets of lights. So if you add that probability onto your 0.46 you should get the correct answer.

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Hope this helps, if not let me know 🙂

minor summit Nov 8, 2022, 10:00 PM

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Ohh thankss , I managed to get the solutions, has to do 0.6 x 0.7 and then 1 - 0.42

shell pelican Nov 8, 2022, 10:01 PM

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Yh so the final answer was 0.58?

#probability 3