#differentiation
10 messages · Page 1 of 1 (latest)
what part
So differentiate and solve the derivative and just plot it
i've got f'(x) but where do i sub x = 0 and y = 0 to find where the points meet the axis
Well x=0 is y intercept which is just 9
And y=0 gives a solvable quadratic where the solutions are where it crosses x axis
f'(x) = 3x^2 - 12x + 9
set equal to 0 and solve
(3x-3)(x-3) = 0
x = 1, x =3
y intercept is where x = 0 so its at (0,9)
i was confused on whether to sub x = 0 into f(x) or f'(x)
your sketching f'(x) so sub it into that
ohh