decades into words

[wooden valley]

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* · Jan 3, 2025, 4:20 PM

[ionic berry]

maybe there is a function, but spontaneously my solution would be kind of like this

def decade_to_word(decade: int) -> str:
    match decade:
        case 1980:
            return "ninteeneighties"
        case 1990:
            return "ninteenninties"
        case 2000:
            return "twothousands"
        case _:
            return "something else"

print(decade_to_word(1980))

output:

ninteeneighties