print out the internal field name where the methode was returned too

[fossil bridge]

    public static List<Species> jannaPokemonList(Predicate<Species> lambdacondition) {
        List<Species> all = getAll();
        all.removeIf(lambdacondition);

//TODO print the field?     
   System.out.println("§c["+all.size()+"]\n§f");
        all.stream().sorted(Comparator.comparingInt(Species::getDex)).forEach(a->System.out.println(a.getDex()+": "+ a.getName()));
        return all;
    }

basically i have this bad boy, and when i run the code i get nice long lists of data, the problem is. i dunno which list is what. so i want to somehow get the field name, so i know which list it is.

how would i able to do this?

[haughty sail]

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[stone ravine]

    public static List<Species> jannaPokemonList(Predicate<Species> lambdacondition) {
        List<Species> all = getAll().removeIf(lambdacondition);

u can write it like this instead

also, it shouldnt be called 'lamdacondition' the name describes nothing

ignoreCondition?

    all.stream()
        .sorted(Comparator.comparingInt(Species::getDex))
        .forEach(a->System.out.println(a.getDex()+": "+ a.getName()));
    return all;
  }

u shouldnt write funcional pipelines in a single line
put each expression on its own line

and u should look at overriding the toString method on the Species class to be a.getDex()+": "+ a.getName()
that way u can write:

    all.stream()
        .sorted(Comparator.comparingInt(Species::getDex))
        .forEach(System::println);
    return all;
  }

and u should make Species implement Comparable so that u can change it to:

    all.stream()
        .sorted()
        .forEach(System::println);
    return all;
  }

as for knowing which field it is ....... i'm not even sure what ur asking
if u want to be able to identify each list seperately
then register each query and assign it an ID and print the ID out tooo