error in the code

[sour light]

the code below should return true for input n=10 and k =3 but it is giving false,

it's as if while execution it is ignoring if part,it is getting executed if I comment the else part

class CheckBit
{
// Function to check if Kth bit is set or not.
static boolean checkKthBit(int n, int k)
{
// Your code here
boolean a;
String bina=Integer.toBinaryString(n);
char aa=bina.charAt(k);
if(aa==1){
a=true;
}
else {
a=false;
}
return a;

}

}

[uncut zodiac]

⌛ This post has been reserved for your question.

Hey @sour light! Please use /close or the Close Post button above when your problem is solved. Please remember to follow the help guidelines. This post will be automatically closed after 300 minutes of inactivity.

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[uncut zodiac]

Please format your code to make it more readable.
For java, it should look like this:
```​​​`​java
public void foo() {

}
​​​`​```

[sharp mauve]

you are comparing a char to an integer. Compare a char to a char

[sour light]

but chat gpt said In Java, you can compare two char values using the equality operator (==).

[sharp mauve]

yeah but one is not a char.
this is a char'1'
this is an integer1

look at this line closely: if(aa==1){

[umbral edge]

i updated it to char aa=bina.charAt(k);
char a1='1'; if(aa==a1){ a=true; } but it is stall not working

This message has been formatted automatically. You can disable this using /preferences.

[sharp mauve]

the first bit is the one to the very right:
3 in binary is 11
the first bit is the rightmost 1.

[sour light]

n=10 and k =3

it's checkinig for 10 not 3

[sharp mauve]

10 in binary is: 1010
Your current implementation returns the red 0. By my understanding it should return the blue 1.

[sour light]

that's what I am asking why is it returning 0 instead of 1

[sharp mauve]

because you are looking at it from the wrong side. The red 0 is the first bit, not the blue 1.

[sour light]

thank you got it

[uncut zodiac]

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