Determining character type

[dawn dagger]

1. String methods
2. Array

This is the problem. How am i supposed to solve it? Isn't there any other way to do it without writing 50+ if - else if statements to do it?

[thick spade]

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[rigid sparrow]

well there's this thing called ascii ranges

your character is just an integer at the end of it, you can check if the character is in a specific range to classify it

with that last statement, you can effectively check if character T is between A and Z

[dawn dagger]

what about special characters?

[rigid sparrow]

did the problem define what special characters are

for all we know, special characters are just outside of the range of everything else we can classify

[dawn dagger]

nah

[rigid sparrow]

then its probably this

[dawn dagger]

that means, if i can satisfy that the character is not alphaneumeric and not a number, then its a special character right? @rigid sparrow

[rigid sparrow]

yes

probably

[dawn dagger]

w8

lemmi see if it works

how can i check if it is a number?

does character == int.class work???

@rigid sparrow

[rigid sparrow]

no

[dawn dagger]

uh, then?

[rigid sparrow]

use this

character >= '0' && character <= '9'

just put your own values in it

as mentioned, each character has an id attached to it

like you can see in that screenshot

eg 0 has id 48, / has id 47, etc

and since the devs of that standard were smart enough to put related characters together, you can basically check if a character is of a specific type just by looking if its in the right range or not

you gotta be careful with letters tho, upper and lowercase letters have different ranges

[dawn dagger]

okay, but now i am stuck in another problem...

which method is used to take char as input?

from the scanner class?

[rigid sparrow]

try scanner.next(".").charAt(0)

or just scanner.nextLine().charAt(0)

[dawn dagger]

CharacterDeterminant.java:7: error: non-static method nextLine() cannot be referenced from a static context
char character = Scanner.nextLine().charAt(0);
^
1 error
error: compilation failed

it returned this

w8

i don;t need a character, i can simply use string

nah i have to use character

[rigid sparrow]

well you do need a character to check

[dawn dagger]

yeah

[rigid sparrow]

you need to make the scanner first before using it

[dawn dagger]

you mean the scanner object?

[rigid sparrow]

Scanner scanner = new Scanner(System.in);
char character = scanner.nextLine().charAt(0);

[dawn dagger]

yeah

finally it worked...

thank you very much @rigid sparrow

[thick spade]

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