Anyone know why my vararg method wont accept multiple Strings?

[wary notch]

    public int getMenultem(String...options) {
        String[] menuList = {"1 - Encrypt text", "2 - Decrypt text", "3 - Display ecrypted list", "4 - Exit"};
        boolean loop = true;
        int x =0;
        
        do {
            for (String list : menuList) {
                System.out.println(menuList[x++]);
            }
            x=0;
            System.out.print("Enter value: ");
            if (keyboard.hasNextInt()) {
                userInput = keyboard.nextInt();
                if (userInput > 0 && userInput < 5) {
                    System.out.println(userInput);
                    loop = false;
                } else {
                    System.out.println("\nPlease enter an integer within range");
                }
            } else {
                System.out.println("\nPlease enter an integer");
                keyboard.next();
            } 
        } while (loop);
        
        return 0;
    }
    
    public String getString(String prompt) {
        return prompt;
    }
    
    public int getInt(String prompt, int min, int max) {
        return 0;
    }
    
    public Encryptable getMethod() {
                //This does not work!!!!
        int x = getMenuItem("1 - Encrypt text", "2 - Decrypt text", "3 - Display ecrypted list", "4 - Exit");
        
    }

[vagrant siren]

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[barren bough]

what do you mean by "does not work"

[barren bough]

ah

public int getMenultem(...) {...}
int x = getMenuItem(...);

look at the names very closely

[wary notch]

i love you

close

thank you for your help

[vagrant siren]

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