{
for(int j = 0; j <= i; j++)
{
stringBuffer.append(color1);
}
for(int j = i; j <= (size * 5); j++)
{
if(i == 0 || i == (size-1))
{
stringBuffer.append(color2);
}
else
{
stringBuffer.append(color3);
}
}```#Does anyone know how to reverse this code?
ionic briar
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ionic briar
i want to make this
but i currently have this
which is why i want to reverse the code i have posted above (it's the second half of the flag
ionic briar
hahaha
mossy spruce
sec
ionic briar
kk cool thanks!
mossy spruce
what are color1, color2, color3, size? just so i can get my bearings a bit quicker
also where are you adding newlines?
mossy spruce
getVerticalBars(10, 12, 3, 'R', 'G', 'B');
that doesn't really tell me what i need
also what?
ionic briar
{
StringBuffer stringBuffer = new StringBuffer();
for(int i = 0; i < size; i++)
{
for(int j = 0; j <= i; j++)
{
stringBuffer.append(color1);
}
for(int j = i; j <= (size * 5); j++)
{
if(i == 0 || i == (size-1))
{
stringBuffer.append(color2);
}
else
{
stringBuffer.append(color3);
}
}
stringBuffer.append("\n");
}
for(int i = 0; i < size; i++)
{
for(int j = 0; j <= i; j++)
{
stringBuffer.append(color1);
}
for(int j = i; j <= (size * 5); j++)
{
if(i == 0 || i == (size-1))
{
stringBuffer.append(color2);
}
else
{
stringBuffer.append(color3);
}
}
stringBuffer.append("\n");
}```why would you not provide the entire code
ionic briar
people have gotten angry at me previously for posting too much code lol
steady berryBOT
mossy spruce
try having a read at that
mossy spruce
people have gotten angry at me previously for posting too much code lol
in response to this, not your code
the amount of code is fine, it's just really spread out (a lot more newlines than most people would prefer)
ionic briar
it's for comments haha (im dumb and add them in at the end lol)
mossy spruce
the main part is you need to show all the relevant stuff
truncate as much excess as you can, but don't remove stuff that's actually important
mossy spruce
it's for comments haha (im dumb and add them in at the end lol)
why do you need to have empty lines prepared though
ionic briar
i need to be very descriptive for the school im in
basically have to describe everything im doing
mossy spruce
no, why can't you just add the lines for the comments afterwards
ionic briar
idk tbh, it's just the way ive been doing it
mossy spruce
if you aren't going to be commenting along with writing the code, then just focus on the code, worry about comments later
ionic briar
yeah youre right
mossy spruce
anyways, you have 2 main loops, both using for (int i = 0; i < size; i++)
each of those correspond to half of the output you have rn
looks like the shape of it is dependant on i, so you need to change how i behaves, the order of values given as i
so the first loop would be unchanged, but for the second loop, since you need to reverse the order of how it iterates, you need to change where i starts and ends accordingly
you need it to iterate opposite the first loop, how can you do that
ionic briar
Would i be changing the starting point of i in the second half of the flag?
mossy spruce
yes
ionic briar
for(int i = size ; i > 0; i--)
hows this?
hey you there?
{
for(int j = 0; j <= i; j++)
{
stringBuffer.append(color1);
}
for(int j = i; j <= (size * 5); j++)
{
if(i == 1 || i == (size))
{
stringBuffer.append(color2);
}
else
{
stringBuffer.append(color3);
}
}
stringBuffer.append("\n");
}```ive made some progress
now i have an extra r sticking out though
how do i get them to shift back once?
mossy spruce
sorry
passed out
think of the values that your original loop goes through
suppose size is just 5 for simplicity
the normal loop will go through 0, 1, 2, 3, 4
so you need to reverse that, 4, 3, 2, 1, 0
right now you have 5, 4, 3, 2, 1
mossy spruce
@ionic briar