#how to do this polygons

45 messages · Page 1 of 1 (latest)

wraith anvil
low moatBOT
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low moatBOT
fresh trench
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Use [180(n-2)]/n, where n is the number of sides of the polygon

wraith anvil
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ok ty

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how do i close

fresh trench
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It should be +close

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I take that back

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It should just be 180°(n-2)

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The extra n divisor is for an individual angle

wraith anvil
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aight

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how am i supposed to do this

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where there are 2 angles missing

frail citrus
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So you can find the sum of the missing two angles

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then half it

wraith anvil
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hows this in any way helpful

frail citrus
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seems pretty straightforward

wraith anvil
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how am i supposed to find the sum of the 2 angles

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like wtf

frail citrus
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sum of interior angles - angles known

wraith anvil
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ok

wraith anvil
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this is some low effort responses

frail citrus
wraith anvil
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i am

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i cant say the same for u

frail citrus
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What u want

wraith anvil
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more effort response

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i already got it though

frail citrus
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im not giving u the answer

wraith anvil
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im not asking for the answer

frail citrus
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Sure

wraith anvil
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ok

low moatBOT
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@wraith anvil

<:HelpIcon:1304095958283321385>| Help Reminder

Hello quan_dingle1, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.

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@frail citrus @fresh trench The user still needs help with this help request.

fresh trench
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What do you still need help with

mental pagoda
# wraith anvil ok

well there is this formula to find the total sum of interior angle for any given polygon: (2n-4)90

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where "n" is the number of angles in a polygon

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for urs its 6, so plug in 6

fresh trench
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You can also do 180(n-2)

wraith anvil
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nvm

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i got it

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I literally did the test like 5 mins ago