#Reducibility of a polynomial over all finite fields

8 messages · Page 1 of 1 (latest)

white karma
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Hi, I want to ask if there's other solution for (b). I used the legendre symbols to prove at least one of 2,7,14 is a quadratic residue, and the rest is trivial

Thank you so much if you could provide other ideas or related problems.

opal marsh
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If so this isn’t the right channel

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But to answer your question yes you can solve b differently

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Actually you can use (c) to solve (b)

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because P being irreducible mod (p) implies that Gal(K/Q) contains a 4-cycle (if you see it as a subgroup of S_4) notably it contains an element of order 4

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but you can see that this isn’t possible

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Up to you to see why