#How to solve for n 1553*0.96^n<500
31 messages · Page 1 of 1 (latest)
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you can use any base
doesn't have to be 0.96
How so can you détail the formulas and explain?
use the property of logarithms
I don't understand that property
you can see on the third one
if you take the log of a power
the power becomes the coefficient
Okay do I need to do something else to the other side of the inéquation? Like the 500, do I need to apply a log to it
Yes
Why
because you apply log to both sides
But that's the part where I'm stuck, if logx^n = nlogx then I can't I just replace the left side by it
Yes?
that's a property of logaithms
But that's if you already divided both sides by 1553
I don't understand here's my logic I divide both sides by 1553
0.96^n=500/1553
I apply the property :
nlog(0.96) = 500/1553
Since they're both equal
And I divide by it
n= 500/1553/log(0.96)
you need to apply log to both sides
you can't just apply it to one side because then it's not equal
If i have sqrt(x^2) = 500 then I can just say x=500
nlog(0.96) is not the same as 0.96^n
Then why the heck is it written logx^n = nlogx
0.96^n does not have a log next to it
you cannot use the property
Oh I see it's like we're transforming both sides
Yes
@tardy karma
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