#How do u actually do this

55 messages · Page 1 of 1 (latest)

hollow zephyr
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Idk the mark scheme doesnt help ans also it says stuff about cyclic quadrilateral when the wuad isnt cyclic sonit makes no sence

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dusk thornBOT
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dusk thornBOT
hollow zephyr
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<@&1309522179368419349>

vocal girder
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You from a cyclic quadrilateral

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And the angle is half the angle at the centre by circle theorems

hollow zephyr
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Hold i gtg for dinner ill talk after

vocal girder
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No problem

hollow zephyr
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@vocal girder

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im back btw

hollow zephyr
vocal girder
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Angle at the centre is double the angle at the circumference

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I'm assuming that's what they meant by cyclic quadrilateral

hollow zephyr
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ik the circle theorims

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but there is no cyclic quad

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cyclic quad means all the corners tocuh the edge

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touch

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@vocal girder

vocal girder
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This is what I meant

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You can see that the angle forms two edges

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Which allows you to form a cyclic quadrilateral

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And this is true for any point on the circumference in that arc

hollow zephyr
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ok but how is that helpful

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like i still dont understand how to do the Q

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the mark scheme basically just says nothing

vocal girder
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Hm

hollow zephyr
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@vocal girder

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i did it

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the only part i dont get is

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when i said that BPC = 180 -x. (which is allowed according to mark scheme)
how do we know that ABPC is a cyclic quad (hence why the fact that opposite angles add to 180)?

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@vocal girder

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..?

vocal girder
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Sorry bro I'm busy atm

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Lemme see

hollow zephyr
vocal girder
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Sorry I'll do it when I'm back home

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In like 10 mins

hollow zephyr
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alr np

vocal girder
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as you can see

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There's other methods which you can use

vocal girder
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BPC is not 180 - x because of cyclic quad

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there are literally 2 right angles in the quad

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that's why it's 180 - x

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Also

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It only says 3 reasons

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So you don't even have to use cyclic quadrilaterals

hollow zephyr
hollow zephyr