#Help with the maths side of a physics problem

44 messages · Page 1 of 1 (latest)

trim mortar
#

Im supposed to find the velocity of 2 lines for a practice problem, one issue, is that they both cannot be the same, distance/time is also the same as getting the gradients, which i solved as 2.5, but that both cant be 2.5 when one is clearly at a higher include, context of the question:
"Have a look at the graph below which gives the position of a robot against time. From 5 to 10 seconds the position is changing more per second than from 0 to 5 seconds, so we expect the velocity is higher. We can find the velocity of the robot in each of these time intervals using equation 1 or by finding the gradient (slope) of the graph. "

image-1.png image-2.png
shadow condorBOT
#
👋 Welcome to your Help Thread!

Hey @trim mortar, Thanks for sharing your math problem with us. While you wait for a Helper to help you, we want to share some vital information with you.

●

Please take a moment to read the helpee guidelines. This will make sure that your post follows the helpee rules of our community.

●

Please don't ping <@&775784618955505685>, <@&1283689826742440016>, <@&819616364188139550>, or <@&624327278137966593> for help because their job is to take care of the server's administrative tasks, not to answer queries directly. However, if you have a problem with how a Helper is acting, you can ping a Helper Moderator.

●

It's always very useful if you can show us the work you've done so far. This makes it easier for our Helpers to find mistakes and help you get to the right answer.

Once you've got your answer and you're all set, you can close this thread by typing +close, and then you can click the Thank buttons to show your Helper some appreciation. ·
shadow condorBOT
molten crown
full basin
ornate siren
#

Okay so

#

When you're taking the velocity for the second one

#

You're only finding the slope for the second line, so best option here, is subtract the x and y values where line 1 ends

#

Otherwise you're also taking distance/time for both lines

#

I assume it ends at around (5,12)

#

So try taking (15-12)/(6-5)

#

Funniest bit is, this is the exact formula for the slope

cobalt junco
ornate siren
#

I think the value for line one is 2.5, not 2

full basin
ornate siren
#

Oh lol I didn't realise it didn't start at origin

full basin
ornate siren
#

Around 2

full basin
#

(12.5-2.5)/(5-0)

ornate siren
#

That is, if you assume the values are whole numbers exactly

#

Which is why I said 'around' everytime

full basin
#

yes, i assumed them to be exactly the midpoint

#

okay fair

#

and what do you get for V2

ornate siren
#

Around 3?

ornate siren
ornate siren
full basin
#

yes

full basin
trim mortar
#

Sorry ill have a look at all things said tommorow

#

i been really busy with other question stuff

full basin
trim mortar
#

tommorow definitely

trim mortar
#

Ok

#

so

#

Looking at everything

#

and checking with some other people

#

this seems to be correct

#

+close

shadow condorBOT
# trim mortar +close
Please thank your Helpers before closing!

Please thank the helpers who assisted you by clicking the buttons below. You can thank each helper only once. Once you're done, click "Close Post" to close this thread.

shadow condorBOT
# shadow condor

Thank you for your feedback! dyck path has been awarded 1 :helper_points:. They now have 2 :helper_points:. They have 3 :helper_points: daily left for today.

shadow condorBOT
# shadow condor

Thank you for your feedback! Hades has been awarded 1 :helper_points:. They now have 3 :helper_points:. They have 3 :helper_points: daily left for today.

shadow condorBOT
# shadow condor

Thank you for your feedback! Anukalp Jha.dev has been awarded 1 :helper_points:. They now have 3 :helper_points:. They have 3 :helper_points: daily left for today.