Help Trigo! Pls🙏

[clever rock]

Illustration + how to solve this. I'm very dumb

[midnight torrent]

👋 Welcome to your Help Thread!

Hey @clever rock, Thanks for sharing your math problem with us. While you wait for a Helper to help you, we want to share some vital information with you.

​

● Please take a moment to read the helpee guidelines. This will make sure that your post follows the helpee rules of our community.

​

● Please don't ping <@&775784618955505685>, <@&1283689826742440016>, <@&819616364188139550>, or <@&624327278137966593> for help because their job is to take care of the server's administrative tasks, not to answer queries directly. However, if you have a problem with how a Helper is acting, you can ping a Helper Moderator.

​

● It's always very useful if you can show us the work you've done so far. This makes it easier for our Helpers to find mistakes and help you get to the right answer.

Once you've got your answer and you're all set, you can close this thread by typing +close, and then you can click the Thank buttons to show your Helper some appreciation.

[torn dome]

can u draw

the ships

[clever rock]

No that's why I'm asking for help on to how to illustrate it cause I can't imagine it

[torn dome]

draw a horizontal line as reference

one ship sails at 125 degrees to this line

can u draw an arrow at 125 degrees to this line?

[torn dome]

roughly! u dont have to draw the exact thing ofcc

[clever rock]

Wait wait ✋️

Like this?

[torn dome]

correct

draw another arrow at 230 degrees

[clever rock]

Uhm, separate or still somewhere in here? (I'm sorry I'm dumb)

[torn dome]

listen

the first line u drew

the horizontal one

it represents (according to the question) "the port"

u shouldnt draw it seperately of course

[clever rock]

Then is it smthng like this

[torn dome]

its 230 degrees with respect to that horizontal line!

imagine that the first ship wasnt there how would u draw the second ship at 230 degree to the horizontal line?

the horizontal line means the reference line ( the --> one)

[clever rock]

Oke last one,,, is it smthng like this or should I just yeet myself now

[bronze solstice]

You labelled the wrong angle 230

That’s less than 180

[tall cobalt]

knots are the speed units, I suppose

[clever rock]

This is my current progress. I'm currently lost on how to get the bearing. I got the angles and the sides. Tho haven't wrote the angles yet

[tall cobalt]

Nice

Triangulation

[clever rock]

Dyk how to get the bearing?

[tall cobalt]

Yes

[clever rock]

Do u mind teaching me

[tall cobalt]

sure

$ship_{Ax}= 18cos(125 deg)$

[unique kraken]

André

[tall cobalt]

$ship_{Ay} = 18sin(125^{deg})$

[unique kraken]

André

[clever rock]

Sht I'm so unfamiliar with what I'm looking at

[tall cobalt]

It just represents its position

[clever rock]

Ain't it not allowed to go negative

[tall cobalt]

uh?

hold on

look

That is just how it looks when graphed

wait a bit, just let me cook

we are just gonna subtract ship 2 from ship one

lol

[clever rock]

Oh mb we don't use that

[tall cobalt]

No worries

it's simple

ship 2 has 24 knots and a rotation on the x-axis of cos(230 deg)

so 24 * cos of (230 deg)

for the y-axis, we have 24 * sin of (230 deg)

We compare them like so:

$distance_x = |18cos(125 deg) - 24cos(230 deg)|$

[unique kraken]

André

[tall cobalt]

$distance_y = |18sin(125 deg) - 24sin(230 deg)|$

[unique kraken]

André

[tall cobalt]

Now, we find the hypothenuse of your triangle!

[clever rock]

Uhh I got 100.6 for hyp

[tall cobalt]

$\sqrt{|18cos(125deg) - 24cos(230deg)|^2 + |18sin(125deg) - 24sin(230deg)|^2}$

@clever rock, it's this one

[unique kraken]

André

[clever rock]

Imma be real honest but like, I don't get it

Rather we uses the law of cosine formula and so I got 100.6. As for illustrating graph we uses only 4 directions by drawing it and nothhing,, so I'm quite confused rn

[tall cobalt]

uhm

you should be getting the correct one? (like 33.52 knots)

[tall cobalt]

what method were you trying to use prior to my solution? Maybe you are mixing up some things?

[tall cobalt]

I will graph it rq

[midnight torrent]

@clever rock

:HelpIcon:| Help Reminder

Hello ayii.lin.__, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.