#8th grade math, algebraic fractions and formulae
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need help with a) and b), and maybe some help understanding this topic overall. thanks in advance
Okay, so.
When we talk about doing algebra.
What we're really doing is transforming equations into other equations.
And we're doing this in specific ways.
Specifically, an equation is a statement.
Therefore it has a truth value.
whats a truth value
True or false.
i see
And we want the new equation to have the same truth value as the old one.
Right, so.
The rules are, if a = b, then: a + c = b + c a - c = b - c ac = bc a/c = b/c (if c =/= 0)
ohh i see
So we begin with the equation (3a + 2)/20 = 5/(3a + 2)
mhm
What we want to do is find the value of a that makes the equation true.
Like I said, we can add, subtract, multiply, or divide the same thing on both sides.
oh yeahh
So what should we do on both sides?
in my opinion maybe make them like not be a fraction?
dont really know how to phrase it
How do we do that?
cross multiplying it?
Again, we have to multiply the same thing on both sides.
3a+2/20 times 20 = 5/3a+2 times 20?
Right.
it'll remove the denominator from 3a+2/20
then uhh 5/3a+ 2 times 20 times 3a+2
(3a+2)^2
(3a + 2)/20 = 5/(3a + 2) if and only if (3a + 2)/20 * 20 = 5/(3a + 2) * 20.
Remember, x = y if and only if zx = zy. Here, x = (3a + 2)/20, y = 5/(3a + 2), z = 20.
Now let's simplify this equation before moving on.
We get 3a + 2 = 100/(3a + 2), right?
yep
So what should we do next?
Right. 3a + 2 = 100/(3a + 2) if and only if (3a + 2)^2 = 100.
Now, another rule is that a^2 = b^2 if and only if a = b or a = -b.
Because what's (-b)^2?
Right.
So we have 3a + 2 = 10 or 3a + 2 = -10.
wait what
It could be either.
no i mean like how did u get this
Because (3a + 2)^2 = 100.
oh u sq rooted it?
In a way.
Because if 3a + 2 = -10, then (3a + 2)^2 = 100.
oh wait yeah i keep forgetting negative multiplied by negative is positive
alright thanks
So now we have two equations, and we have to solve both, and then check the solutions.
check the solutions?
sorry for not understanding certain terms, the education system here is quite different in a sense
Yes. It's possible we get what are called "extraneous" solutions.
i've never heard of that term before
Remember what I said about transforming equations into different equations with the same truth value?
yeah
That doesn't always exactly work.
Sometimes we transform an equation into an equation with more solutions than the original had.
i see
So we have to take the solutions we get and plug them back into the original equation to make sure they really are solutions to that equation.
ohh its like checking if the answer is correct?
Yes.
oh i see i think i did something similar to that when i was learning simultaneous equations
So, returning to here, which equation would you like to solve first?
probably the positive one
So we have 3a + 2 = 10.
3a +2 -2= 10-2
3a= 8
a= 8/3
is that right?
And now we check, is it true that, if a = 8/3, then (3a + 2)/20 = 5/(3a + 2)?
alright i'll grab my calc
(3x8/3+2) divided by 20= 0.5
5/(3x8/3+2)= 50
its false i think
or i made some mistakes while inputting the numbers in my calc
I think you made a mistake.
Calculator mistake.
(3a+2)/20 is
3a= 3 times 8/3
3a = 8
8+2=10
10/20= 0.5
5/(3a + 2) is
3a= 3 times 8/3
3a= 8
8+2= 10
5 divided by 10= 0.5
wait i gotta edit it
oh its divide mb wait
alright yeah its true
Great. Now we solve the other equation.
And now we check that solution.
mm
are they both similar?
if yes then i'll give it a shot
thanks for the in-depth explanations
have a great day

i'll leave this open for now in case i cant solve B
You could show your work in the thread if you like.
alright I'll show it when Ive finished it and y'all can "mark" it since my teacher is on holiday
like verify is my answers are right or wrong
or i could just check the solution
im unsure on how to do b)
working done is still the same
Okay, let's think about it. We begin with the equation 36/x - x = 5, correct?
yep
Now we can do the same thing to both sides of the equation. What should we do?
That is true if the original equation is true.
wait
my friend did say i forget to do something
other qn u forgot times an x on the rhs
jaydernn
[ROLI]
— Yesterday at 12:40 PM
what
Greg 👍
[ASTD]
— Yesterday at 12:40 PM
becuz urfirstequation times an x first
but u nvr times the x to the rhs
alright
is this correct?
Yes. You multiplied the same thing on both sides.
alright'
oh yeahh sorry for the mistake
what does this mean?
It means we want to know what number x is equal to.
Right, because then we can only know what number x is if... we know what number x is.
Right.
Now, this is what we call a quadratic equation, and there are a few different ways to solve it (that are really the same way).
i see
Here's one way we call "completing the square".
First, we need to get all our x terms on one side.
We need x terms on one side, numbers on the other.
ohh i see so now all the x terms are on one side
yep
So if 2yx = 5x, what happens when we solve for y?
...no.
Therefore?
2.5x?
wait
where did the y come from? or was it just an example
sorry im really confused right now
yeah the algebraic identity
It's called "completing the square" because we add the thing to both sides that we need to get a perfect square on the left side.
oh
If y = 2.5, then we have x^2 + 2 * 2.5 * x + 2.5^2 = (x + 2.5)^2.
wait sorry i have to eat lunch now
I might not be here when you get back, it's late for me.
and i'll be away so yeah, thanks for the help for now
its okay, get some rest. maybe my teacher can help me too
thanks for the help
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thanks'!
is y=2 in this case?
i've checked my solutions and it seems to be wrong. y=2 is false
since if y=2, the -1/y-2 part would essentially be -1/0
math error
so yeah
You made a mistake.
where was the mistake
First line to second line.
Very smart
Also, more generally, I think until you have a more solid intuition that you should do it explicitly and exactly the way I taught you; take the equation and do the same thing on both sides.
I see alright thanks