#If p < q are two consecutive odd prime numbers, show that p + q has atleast 3 prime factors
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If p < q are two consecutive odd prime numbers, show that p + q has atleast 3 prime factors
q = p+2 ??? Explain?
@ripe aurora
It's not necessarily true
For example 7 and 11
No 2k seems fine
OK so are you aware that any composite number greater than 1 has atleast 2 prime factors
No im not aware abt that
But that's true
So based of this
We get at least 2 prime factor
But we still need one more
Are you sure? You should look up the proof of why composite numbers greate than 1 have atleast 2 factors
What if (p+q)/2 is R and R is prim
Sum of 2 consecutive primes / 2 , prime?
Why it isn't?
So let's start with little basic stuff
a+b/2 lies between ?
A and b
Yup
p and q are consecutive primes
There are no primes in between them
So It's can't be prime
This is only true for consecutive *
Yeah we have 2 as one of the factor and 2 others
Yup since it was composite
Maybe not all quora answer is right
Don't forget to look up the proof of why composite number have 2 prime factors
Yeah at least 2 prime
Yeah it's kind of simple really but still very imp
Goodbye anywah hope we meet again
If it doesn't have 2 prime factors then it will be prime itself
+close
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