someone help please

[raw heron]

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[dim magnet]

So we want B to have an equal number of all balls, right?

So one thing we need is for red and green balls to be equal. What has to happen for that?

And if we take away a red, what number of reds and greens do we have?

So what number of yellows do we need for adding one to give us 4?

...0 + 1 = 4?

...because we're adding a yellow ball.

Like you said.

Yes, therefore we need n + 1 = 4.

You're saying n = 0.

Right.

Well, no.

Show your work on that one.

Why 5?

Okay.

So now you have to calculate the probability of each case occurring, given the appropriate value of n, bearing in mind that you first move a ball from A to B, then move a ball from B to A.

Therefore you must account for the risk of moving the same ball both times.

Show your work.

[distant spruce]

@dusky haven

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