#Sum of Series
39 messages · Page 1 of 1 (latest)
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what i've done:
Opening the series i notice 3 ^ (102/103) = 3^(1 - 1/103)
using this fact
i start pairing kth term from starting and ending
and solved the question
but what i want
is
to
like
make this nth term into a telescopic term or something
like solve it within this sigma sign without opening the entire series
You can just switch the order of the sum by turning n->103-n
Hence adding them you get what you desire
isnt that eventually what i've done??
1st term + last term
ive mentioned that, please read my initial messages
Am I allowed to post the solution here? Or should I dm you?
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You asked to "solve it within the sigma sign", so that's how you do it
Quite literally, your concept in a finite notation
Like, helping with hints rather than providing full solution?
yeah just let m=103-m and youll be fine
it simplifies well from there
Hint: ||Try cancelling out the common term in the expression||
oh yeah thanks
THANKYOUUU
whats common in there?
No problem :)
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