#how to solve for theta
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Note that 1/cos(θ)^2 = 1 + tan(θ)^2, so this is a quadratic equation in tan(θ).
Also, please, don't solve it like this. Leave the parameters as variables and substitute their values at the very end.
Bruh this physics 12 wants me to know that sinθcosθ is 1/2sin(2θ)??
Do I memorize this stuff
Why's 1/2sin(2θ)
wdym
just use angle addition
$\sin(x+x)=\sin(x)\cos(x)+\sin(x)\cos(x)=2\sin(x)\cos(x)$
ooaa
also aren't you just supposed to let $x=v\cos(\theta)$ and $y=v\sin(\theta)-\frac12gt^2$
ooaa
+close
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