My actual travel distance was 3.44 miles, and I am trying to use riemanns square to estimate my travel distance. All of my estimates (RRAM, LRAM, etc) are overestimates. Are they correct? I need help
#RIEMANN SUM to find estimate of distance travelled
320 messages · Page 1 of 1 (latest)
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Good lord
I'd just do it in Excel...
But it’s on paper, it’s paper project
Quite a hassle to do all that by hand.
what
Surely they don't expect you to write the full sums of dozens of terms.
We can use a calculator but we have to write the work we do on paper
😡
Like where is your right riemann sum?
Dude cmon
411minutes*MPH or 6.8 miles^2 when converted
Don't be rude.
At least you can check it in Excel.
I am so deadass right now but I cannot see where it is
no, like your actual representation on the graph pictures
I see a left riemann
But it's like mixed with the right riemann
So I can't tell if you accurately derived it or not
Ykwim
yea just take away the leftmost value and there’s the RRAM
that’s what I did I just ignored the leftmost rectangle
And dude base times height times the 1, because there is a change of 1 unit for every minute
Did that answer ur question
I used same graph for RRAM, LRAM, MRAM
and trapezoids
Because lazy
Okay
I'm studying rn
Give me a second
R u still studying
Not now
Yeah, I’ll try to look further now
How did looking further do
My teacher said it’s basically very unlikely that I overestimated every estimate
.
Nah vro 💀💀💀
No one’s checking that 💀
Think abt it bro we will both benefit from this bro
Way too much work
No, not really
I have a question.
Make a new help post
Yes
It’s literally one question. Nothin major. What’s 24 divided by 2?
Torrent save me
Check your answers with a calculator
Thanks
I did - I used scientific calculator and Desmond
Desmos
And did your answers check out?
Is there another calculator I should use?
They are all overestimates
Which apparently never really happens
Can you put the data into excel at least
Yeah it wouldn’t make sense
Make it look neat so that I’m actually motivated to help you
Which part needs to look neat
The table of values
OOOOOOO
I’m not reading all that
Organize it and I’ll read it
No, it’s just too much math
@latent spire
Let’s go with trend analysis and see if we can identify a pattern!
Since your scatter plots show data clustering between 20-30 on the vertical axis, we can ask: Is there a clear direction in how the data moves?
- Visual Check: If most points align horizontally, the data might represent stable values over time. If they incline, it could show growth. A decline? That suggests a decrease.
- Possible Correlation: Are the points forming a recognizable shape like a linear trend or curve? If so, I could suggest fitting a function to describe it mathematically.
- Outliers & Variability: Any data points that sit way outside the cluster might represent unique events or errors.
If you want a deeper breakdown, I could explore a best-fit line or another mathematical approach. What do you think?
This was the result of transportation speed during each minute (until 15 minutes is reached). I just want to know if my mile estimations were correct
Bro is this greek 💀
No bro plz
U know calculus PLZ HELP
I will show u a picture of my 3 year old cat if u help
i would love to help except I CANT READ WHATS WRITTEN !!
I WILL REWRITE WHAT CANT U READ
U just summed the datas not the areas 💔
FUCKKKKKKK
what do I do bro
I converted the estimates into miles
Is that not area?
?
WAIT
Changed the MPH*minutes to miles to get area
I’m studying now, I went for a run
Let f(x) be a function such that \int_{-\infty}^{\infty} f(x) , dx converges to the number of socks missing from your laundry. Given that the divergence of the gradient of the curl of f(x) is equal to the number of times you've lost your keys this week, prove that the limit of e^{i\pi} + 1 as x \to \text{your last brain cell} is equal to a pizza with infinite toppings
Wolf id trying
Shut this GPT ahh response up
It’s AI bro
No it’s not.
Anyways if you can’t actually help then respectfully get out
Copilot. Is Artificial intelligence.
Get away
Not AI.
Sure buddy...
ok ask me a question
?!
Can u help plz
Dude just get out seriously
I just need to find area and convert to miles
I’m trying to get this brain dead monkey out
Bro. Im trying to help him out
I’ll try to find the values
I’m a woman
oh shit
Why does everyone think I’m a man
My bad
I can tell you’re not, so I’m going to just timeout you
Arent u only supposed to calculate the low3r and upper 💔 , plus the lower is def lower what are u yappering about
Hopefully that’ll shut you up and make you realize trolling in help threads is not allowed
I’m supposed to calculate the LRAM,MRAM,RRAM, and trapezoid thing
Then convert to miles
-timeout @flat beacon 10m Trolling/using AI in help threads, do it again and it’ll last longer
⏱ Timed out _boogiewoogie__ for 10 minutes
Lemme get on my PC
I could hug u rn thx bro
I’m sorry dude, I’m trying to finish up my mock exam 😭but I’ll let wolf handle it
If his smartass cant I’ll see if I can try again
Ok
I genuinely don't know what MRAM and TRAM are, so i'm sorry i can't lol
i only know upper and lower !!
Middle estimate and trapezoid estimate
Wait how tf are you able to get overestimates and underestimates
Do you have an explicit function that describes whatever you’re trying to integrate??
Like-
The function is the graph
Nah I saw it, you have the actual distance travelled
3.44 miles, right?
I know they’re overestimates because they are higher than my actual travel distance if 3.44 miles when converted
Yes
COOK PLZ
,calc (30+31+39+40+26+16+20+39+18+18+19+29+22+25+27)/60
Result:
6.65
Wtf??
Ok, RRM now
,calc (31+39+40+26+16+20+39+18+18+19+29+22+25+42+27)/60
Result:
6.85
I was surprised
For RRAM?
I mean, I'd still do it in Excel.
Is the MRAM 6.6?
No?
You take the average of the left and right points
Which is also the exact same as a trapezoidal Σ 💀
Whatt
,w Midpoint Riemann Σ
Omg wtf American education is fucking me up
,w Midpoint Riemann Sum definition
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Perhaps try rephrasing your question?
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MMRAM is the same as trapezoidal?
Well the way it was defined to me it looks like it 💀💀💀
How? Do I divide by two? I’m deadass not understanding
Add and divide by 2
No.
Trapezoidal uses (f(a) + f(b))/2, midpoint rectangular uses f((a + b)/2). A bit different.
Yeah I figured 😭
@latent spire your method’s correct
The result will be especially apparently different if the function is convex in the same direction over the whole region of integration (since Jensen's inequality can be applied for every point).
I don’t get how the MMRAM can be applied here 💀
What I did was
That inequality gives me trauma
Oh, if all you have is points and you only use linear interpolation, then trapezoidal and midpoint rectangles give the same thing, as in that case (f(a) + f(b))/2 = f((a + b)/2).
Yeah
We don’t have an explicit function here
I draw line between three points and the middle point got added to the MRAM
then you take all the MRAM points and multiply it by the height of 1
42 is an endpoint
Honestly
I have a hypothesis about what this car is behaving like
Yeah 42 is an endpoint
It was bus drive to school
So you can’t use it for MMRAM
That makes sense
But then you have to account for the last rectangle somehow
oh
I assume the first table is the data you've been given?
If so, I can try calculating the sums, too.
Yea
Personally, this thing’s speed is probably stitched up by a bunch of concave up functions
Alright. I'm going to be busy in several minutes, so please remind me in a couple of hours.
Can MRAM point not be an end point?
Nope
Okok
Ig the only other choice is to ignore it?
Then the approximation will be off
I think trapezoidal and midpoint will be the same tbh
OH WAIT
Linear interpolation
U MAY HAVE COOKED
Because when I removed the 42
My new total distance when converted to miles is
3.3
Which is very close to the actual distance
And isn’t MRAM the most accurate estimate
Opinion?
Also CHATGPT agrees with you on the endpoint thing
Yeah I got 6.6 on trapezoidal, which u got for MRAM, but I got 3.3 (after recalculating now) for the MRAM
Here's what I got.
Is the trapezoidal and MRAM the same?
Yes.
I got 6.6 miles for trapezoidal
For this reason.
How did you get 6.75
Trapezoidal is always equal to the arithmetic mean of left and right rectangles, so no.
Oh
How did you get that? Divide by two after adding LRAM and RRAM?
Then divide by 60?
Well, those are already divided by 60 min/h. Other than that, yes.
Oh
That makes sense
I wonder why my teacher didn’t mention MRAM and trapezoidal are the same
Not in general.
They are only the same when you only have data as points (as opposed to an equation) and when you linearly interpolate the points to get the midvalues.
If you have an equation or you use, for example, quadratic interpolation, then they won't be the same.
Also I wish we learned this faster way, my teacher said to do base1 +base2/2 for every trapezoid
Ok
Well, yeah. We have (for equal intervals):
S(LR) = hΣ(f(x(i - 1)), i = 1 to n)
S(RR) = hΣ(f(x(i)), i = 1 to n)
S(T) = hΣ((f(x(i - 1)) + f(x(i)))/2, i = 1 to n)
From here it's pretty obvious that S(T) = (S(LR) + S(RR))/2.
As for MR:
S(MR) = hΣ(f((x(i - 1) + x(i))/2), i = 1 to n)
So, for T and MR to be the same, we need (f(x(i - 1)) + f(x(i)))/2 = f((x(i - 1) + x(i))/2), which works for linear functions.
OH I SEE WHY WE HAVE DIFFERENT ANSWER
My lord
At 7 it’s 30 not 39
My handwriting is ass sometimes
lol
Sorry
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@latent spire
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