#Definite Integration
54 messages · Page 1 of 1 (latest)
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use kings rule
let u=pi-x
then ezpz
OK let me try that
$I=\int_0^{\pi}\frac{(\pi-u)\sin(u)}{1+\cos^2(u)}du$
ooaa
yws this
Good work
$2I=\pi\int_0^{\pi}\frac{\pi\sin(u)}{1+\cos^2(u)}du\overset{v=\cos(u)}{=}\pi\int_{-1}^1\frac{1}{1+v^2}dv=\pi\arctan(v)\bigg\vert_{-1}^1=\pi\cdot\frac{\pi}2=\frac{\pi^2}2\implies \boxed{I=\frac{\pi^2}{4}}$.
ooaa
this is how i did it
U math major or sorcerer
U skipped every unnecessary thing
U middle school
yes
Which country
guess
China
keep on guessin
It's America
nope
Hint
yeah andromeda
Bro what age ur
India
took you long enough
🤫
Ur 16 or 17
And not in middle school but high school
And u don't know Spanish
2 truths and a lie, which one do you choose?
U learn Spanish on duolingo
U r 18
nope
Chose one finger ✌️
Hm
Jus two question
R u preparing for jee adv thru coaching institute
If yes then how long has it been
no only mains
@high zenith
Hello raunak._.k, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.