#Several geometry questions.

51 messages · Page 1 of 1 (latest)

trim egret
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First one. Find DM + DN in triangle ABC if AB=BC=10 and area of ABC is 50.
I drew the height BK, we know that AB is 10. lets say height is "h" and AK is x. We know that in isosceles triangle height is same as median and bisector. So AK = KC. area of ABC is 1/2 * 2x * h = 50 from here xh=50
also we know that hˆ2 + xˆ2 = 10. But there is no solution. What am i doing wrong

pale charmBOT
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worthy nebula
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I don't quite understand your method

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Ah, I see.

worthy nebula
graceful quarryBOT
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Kocher

worthy nebula
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Basically, you forgot to square the 10 when doing the pythagorean theorem

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Then this leads you to a singular solution

trim egret
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im tired of math

worthy nebula
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I've made worse mistakes _catdespair

trim egret
worthy nebula
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Yes

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Frankly, I don't see how it would help with the question

trim egret
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so im getting -5sqrt(2) and 5sqrt(2) i can pick up only positive one

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then x = y ?

worthy nebula
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Wait forget I said that

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It helps a ton

worthy nebula
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Spoiler: ||ABC has a right angle at B||

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Ok one more thing

trim egret
worthy nebula
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Since there is no given information on MD and DN, we can assume WLOG (without loss of generality) that D is colinear to B

trim egret
worthy nebula
worthy nebula
trim egret
trim egret
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@worthy nebula you here

worthy nebula
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I was out sorry

worthy nebula
worthy nebula
trim egret
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wdym

worthy nebula
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Uh

trim egret
worthy nebula
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You know what

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Take a break

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I gotta take one too

trim egret
# worthy nebula You know what

i know but i cant. Next week i got an exam. Not school exam but government exam. So not passing it wont get me into any uni. Thats why

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yeah i got it man

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@worthy nebula

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from here i get a = 5. and MD = DN. so 2 * 5 = 10

trim egret
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+close

sage pantherBOT
# trim egret +close
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sage pantherBOT
# sage panther

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