#How to proceed ahead what is the meaning of maximum of minimum value here graphically?
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I don't know. There's no total ordering on the complex numbers.
so how do i proceed ahead in this question?
yes, and $z(1+i)+\overline{z}(1-i)\in\bR$
idontknowtherules
Fair. @fringe parcel
bruh i m not getting still ๐ญ
Or is it?
it is
you can proceed
how to ?
As idontknowtherules said, Q is a subset of R.
Wait, hold on, no, Q isn't a subset of R.
That is, the set Q in the problem, not the set of rational numbers.
Forget what I just said, that's wrong.
ok
That said.
so?
...so then the issue of ordering on C returns.
i didn't read the rest of the problem yet gimme a min
The core question is what does it mean to refer to the "maximum" or "minimum" of a set of complex numbers?
graphically *
it says
find when |z-3+2i| is max
for z in P cap Q
Okay.
So that makes sense.
@fringe parcel The way it works is that f(z) = |z - 3 + 2i| is a function from C to R that you're to maximize or minimize.
cant i do it graphically?
Specifically on the subset of C that is PnQ.
how do i find z1 and z2 here?
why do you insist on doing it graphically
isn't that counterintuitive
if you want to do that, then do it, increasing your work ๐ฅ
how algebraically then can u tell
Can you find $P\cap Q$?
idontknowtherules
yeah its clear in the image the intersection of both
i can proceed algebraically as well just guide me
hm you're not willing to do that
i asked you to find PnQ and you just said "intersection of both" instead of a set
anyways
i'll do it graphically just give me a min
|z-3+2i| denotes distance from (3,-2)
yeh
z1 and z2 are labelled correctly here, and they're both on the line joining (3,-2) and (-2,3), the latter point is teh centre of the circle
it passes through the origin ๐ฃ๏ธ๐ฃ๏ธ
and later find point of intersection with circle for z1 and with line for z2
๐
bro check the diagram
hm?
its not passing through origin
yeah so thank u for helping me out
np
btw how to find algebraically?
it's bounded on both sides
so that's only half complete
after that you just bash it
hmm that's longer
didn't realize
gotcha
anyways dw about that
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