#Problem integrals
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You forgot the + C
Remembering your log rules log(3x+3) = log(3) + log(x + 1) which is valid when you account for the constant + C
log xy = log x + log y is valid in the domain of log
$$\ln |x+1| - \ln|3x+3| $$ is a constant, there is no contradiction
aL
calculate definite integral in (a,b) where a >0, say
you get the exact same result
@pastel turtle
@pastel turtle
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because there is an infinity of primitives
btw u did a mistake
u should add the constant C at the end
because the constant C which determines primitive u search
for example ,if we take C = 0 for the first integral and C = -(ln3)/3 for the second integral , we will have the same primitive of the integral
for that the constant C is verry important and u should add it, as i sad because there's an infinity of primitives.