#Augmenting matrices techniques
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I genuinely have no idea what to do to solve this system of equations
I'd probably start with II - I and III + 3I.
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Ok lemme try
Back after so long
Aren't we all travelling
I would try get the top left to be 1x first
Yeah
Same process?
That's basically how rref works
Rref?
Okok
Should I draw u a picture?
No get the top left to be 1 then middle left to be 0 then bottom left to be 0
Find the left most upper non zero entry
Make it one by multiplication or division by appropriate scalr
Use it to eliminate any coefficients below it
Rinse and repeat with the below rows
Yes okay
Eliminate everything below
No.
Not the best idea, that will introduce fractions.
It's harder to work with them.
My mental maths is what is wrong with fractions
I prefer using Gauss's method in such a way that avoids fractions until the very end.
It's 3 equations and 3 variables
What is Gaus’s method
I mean what matters is solving them
It's the method we're using right now...
Yes the earth is revolving around the sun
With the augmented matrices?
You know, the one where you use row operations to bring the matrix to the RREF (or a REF).
Ok, fine. Do what you want.
Yeah
And what would happen if your coefficients were in reals
Still would be able to avoid fractions
That isn't done by hand, then.
Yes it is lmao
I got a question anyway
If darpy is willing to help you with a better shitill leave itto him
Real numbers.
Oh
Idm I already started using your first step
What’s after this step
Bottom equation?
Try it using Redacted's method, then we can use another.
And then eliminate the coefficients above and below
Yes
It adding the second row to above and below won't affect the first column
What
You know what let me do it for you?
Yeah
So, my approach involves making as many small integers as possible.
Here we don't have any leading 1s, but we can make a couple by doing II - 2I, III - I.
Okay hold on
Which row do I apply them to
Of the II-2I on the second row
And the other on the third?
II - I means you subtract the first row from the second.
You might want to write that six at the top a bit better...
It really looks like a zero.
Then the one at the bottom.
The second matrix is after I did the augmentation
You suggested
And then divide by 3?
For first row
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