#Limits

32 messages · Page 1 of 1 (latest)

crude rune
trail onyxBOT
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crude rune
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Hello!

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Is my approach correct?

sharp sonnet
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you made a mistake

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5^(1/n) - 3^(1/n) = (5^(1/n)-1) - (3^(1/n)-1)

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so there should not be a +2

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otherwise it seems good

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@crude rune

crude rune
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Oh ok

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Wait a second I don't understand

sharp sonnet
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-3^1/n-1 is not equal to -(3^(1/n)-1)

crude rune
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how can I substract 1 from each one and not add 2 as a counter

sharp sonnet
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that's your mistake

sharp sonnet
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5^(1/n) - 3^(1/n) = 5^(1/n) - 3^(1/n) + 1 - 1 = 5^(1/n) - 1 - 3^(1/n) + 1 = (5^(1/n)-1) - (3^(1/n)-1)

crude rune
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Oh I get it now

sharp sonnet
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one last thing: can you justify the manipulation you're doing on line 3 ?

crude rune
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It made more sense at the beginning of the limit to just add 2 right away

crude rune
sharp sonnet
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this point is ok

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I'm more concerned about lim n × un = lim n × vn

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unless you know equivalents and you can justify that un ~ vn, it would be better to distribute the n× right away

crude rune
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Ok that makes sense

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Thanks!

sharp sonnet
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you're welcome, you can close the thread with +close if you're finished

crude rune
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+close

sick cragBOT
# crude rune +close
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sharp sonnet
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(and click the buttons)

sick cragBOT
# sick crag

Thank you for your feedback! pétaire has been awarded 1 helper_points. They now have 21 helper_points. They have 3 helper_points daily left for today.