#maths
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you distinguish between x>0 and x <= 0
what do you mean, and why?
consider eq2 |x|+x = 5
either x is negative, either x is nonnegative
if x is negative, then |x|=-x, and this implies 5=0, which is absurd, so no solutions for x negative
if x is nonnegative, then |x|=x, and this implies 2x = 5, so you get x=2.5 >=0 is a solution
thus, the set of real solutions is x=2.5
yess but how do i write an expression without the absolute value sign?
could we do a similar task?
as I said, you have to distinguish with the sign of x
try to do the third one
b?
c
okok
no
ohhh
i see
because if x is negative
then |-x| will be positive
but the other x is still negative
so there is no solutions for x?
on c
yess
is this incorrectly shown then?
what have i done wrong?
i know that the answer is wrong but why did i still get x = -5/2?
to get line 2,you need to assume that x>=0
of course, you are right
so anything you deduce after, you always have x>=0, and -2.5 is not positive
correct
ok i will do the task all over again
but do u have any similar tasks that u would recommend me to do?
there should be other exercises involving the absolute value in your book
well there arent many
then ask your teacher or google them
+close
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