#maths

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narrow brook
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i need help with 2.66 a.
how do i write the expression without the absolute value sign?

pure rivetBOT
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mighty cedar
narrow brook
mighty cedar
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consider eq2 |x|+x = 5

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either x is negative, either x is nonnegative

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if x is negative, then |x|=-x, and this implies 5=0, which is absurd, so no solutions for x negative

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if x is nonnegative, then |x|=x, and this implies 2x = 5, so you get x=2.5 >=0 is a solution

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thus, the set of real solutions is x=2.5

narrow brook
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yess but how do i write an expression without the absolute value sign?

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could we do a similar task?

mighty cedar
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try to do the third one

narrow brook
mighty cedar
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c

narrow brook
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okok

narrow brook
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right?

mighty cedar
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no

narrow brook
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ohhh

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i see

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because if x is negative

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then |-x| will be positive

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but the other x is still negative

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so there is no solutions for x?

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on c

mighty cedar
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you're right, there are no solutions

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on c

narrow brook
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yess

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is this incorrectly shown then?

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what have i done wrong?

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i know that the answer is wrong but why did i still get x = -5/2?

mighty cedar
narrow brook
mighty cedar
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so anything you deduce after, you always have x>=0, and -2.5 is not positive

narrow brook
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correct

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ok i will do the task all over again

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but do u have any similar tasks that u would recommend me to do?

mighty cedar
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there should be other exercises involving the absolute value in your book

mighty cedar
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then ask your teacher or google them

narrow brook
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thanks for the help

narrow brook
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+close

winged mantleBOT
# narrow brook +close
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