#Limits
11 messages · Page 1 of 1 (latest)
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Tried doing everything but answer still comes out as it not existing.
,rotate
would you consider multiplying top and bottom by rt(1+2x) + rt(1-3x)?
that would create a difference of squares on the top, hopefully forcing the x to cancel
@fair nimbus
Ohh, so you can cancel out the x's on a limit then?
Thanks then I got it