#Permutation Problem 3
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midnight pumice
Hints:
Group the 3 books and think of them as a single book
Then think about how the group of 3 books can be arranged or permuted
vivid prism
a) (3!)*(4!) = 144
midnight pumice
midnight pumice
a) (3!)*(4!) = 144
3! X 5!
Use this as a example of few permutations
The group of 3 books may be permuted further along with where they are placed
1- decide Where the 3 books go
2- decide the order in which they are kept
Step 1 gives 5!
Step 2 gives 3!
vivid prism
so in (a) this is what in my mind:
I count the 3 books as 1
There could be 5! possibilities
and each of those 5! possibilities
I multiply it again by 3! possibilities due to the 3-vol book can be arranged 3! possibilities
Is my algorithm correct?
vivid prism
wait let me try b
midnight pumice
Take your time
vivid prism
in (b)
you treat only the 3volBook as one
vivid prism
.close
restive walrusBOT
Unable to parse the channel name
vivid prism
+close