#Factoring
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she hasn’t completed the factorization
Wdym
Well
Then how do I find the complex roots for
x^3 - 3x^2 + x -3
factorize it?
the substitute math teacher did the first step
and presumably someone has completed the second and found (x^2+1)(x-3)
the second of what
Ok but
How is x^2(x-3) + 1(x-3)
step of factorization
The same as
i tend to think about things in steps
it’s equal to this as well, but this isn’t factorized
But is my substitute incorrect
She factored it into: x^2(x-3)+1(x-3) and then she simplified it as (x^2 +1)(x-3)
Is this right?
this is correct
It's just the reverse distributive property.
wdynm
can you demonstrate it
You recall the distributive property of multiplication over addition?
Yeah
Can you explain what it is?
5(2x + 2) = (10x + 10)
something lik ethat
In general, a(b + c) = ab + ac.
Thus, using the symmetric property of equality, ab + ac = a(b + c).
it’s not factorable.
Technically all polynomials are factorable.
Did you write it wrong?
i mean, not with “traditional methods”
just needs to use rational root theorem
what have you been taught so far
like have you heard anything like "rational root theorem" "integral root thereom" smthn like that
@winter salmon
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