#How to find area and perimeter of this werid ah shape
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cut it up into three semicircles
hint: one of them will be a hole
i tried
i think i got it wrong
cause my perimeter is larger than my area
why shouldn't it be?
oh
i got
area= 12.57m^2
perineter= 21.13m
i seem to have a different answer
oh
what did u get
approximately 6.28
how did you obtain your area?
Area of Circle = (Radius)^2
Area of Circle = (Radius)^2
Area of Circle = (2 m)^2
Area of Circle = 4 m^2
Area of One Sector = 1/2 Area of Circle
is there latex on this sever
yes
\text{Area of One Sector} = \frac{1}{2} \times 4\pi , \text{m}^2
you mean π(radius)^2?
ye
latex tweaking
enclose in $dollar signs$
a lot of people
$\text{Area of One Sector} = \frac{1}{2} \times 4\pi , \text{m}^2$
Onyx
$\text{Area of One Sector} = 2\pi , \text{m}^2$
Onyx
Onyx
$\text{Arc Length of One Sector} = \frac{\text{Circumference}}{2}$
Onyx
$\text{Arc Length of One Sector} = 2\pi , \text{m}$
Onyx
$\text{Perimeter} = 2 \times \text{Arc Length of One Sector} = 4\pi , \text{m}$
Onyx
this is the area of what, exactly?
1 sector
wiat hold on
i think im special
what's a sector
or, specifically, which sector
the half circle
waittttt
for the area
cant i just calc the area of a half circle with the raduius 2m?
i got 6.28
ong im special
idk perimaeter
you're going to have to split it up into three arcs
hm ok
is the perimeter of the big arc 6.285
i got 12.56 for the perimeter
am i cooked? or cooking
6.285?
ya
how did you get that
2pir
r=2
and then take half
C=2πr=2·π·2≈12.56637
12.56637/2
so 2π?
6.283185
that's not 6.285
that's 6.283 with rounding
damm ok
so its
uh
and yes, that is the perimeter of the big arc
i still get 12.566
i assume you have found the two smaller ones in a similar fashion?
ye
seems about right
ok
ty
acuatlyy
nah ill do dis tmr
i gotta go be batman
ty for help
@cursive token has given 1 rep to @abstract forum
welcome
shift the piece sticking out into the shape 🔥
@tropic timber
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